Question

A wheel of mass 8 kg and radius 40 cm is rolling on a horizontal road with angular Velocity of 15 rods the moment of inertia of the wheel about its aris is 0:64 Kg/m^2 total Kinetic energy of wheel is answer in j

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Answer 1

Explanation:

your answer is in the picture

Answer 2

The total Kinetic Energy of the wheel is $216J$.

Explanation:

Given,

Mass of the wheel, $m = 8 kg$

Radius of the wheel, $r = 40 cm = 0.4m$

Angular velocity of the wheel, ω$= 15rad/sec$

Moment of Inertia, $I = 0.64 kgm^{2}$

• We know that Kinetic Energy $= \frac{1}{2} mv^{2} +\frac{1}{2} Iw^{2}$

• Putting the values in the above equation, we get,

                         $K.E. = \frac{1}{2} (8)(15$×$(0.4)^{2}$$+\frac{1}{2} (0.64)(15)^{2}$

                                  $= 216J$

Hence, the required value of the Kinetic Energy of the wheel is $216J$.