A wheel of mass 8 kg and radius of gyration 25cm is rotating at 300 rpm.Wat is its moment of inertia
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Answered by
37
Given conditions,
Mass = 8 kg.
Radius of the Gyration = 25 cm.
Using the Formula,
Moment of the Inertia = Radius of Gyration² × mass
∴ I = mr²
∴ I = 8 × 25 × 25 × 10⁻⁴
∴ I = 5000 × 10⁻⁴
∴ I = 0.5 Kgm⁻²
Hence, the Moment of the Inertia of the mass is 0.5.
Hope it helps.
Answered by
11
Mass = 8 kg.
Radius of the Gyration = 25 cm.
Using the Formula,
Moment of the Inertia = Radius of Gyration² × mass
∴ I = mr²
∴ I = 8 × 25 × 25 × 10⁻⁴
∴ I = 5000 × 10⁻⁴
∴ I = 0.5 Kgm⁻²
Hence, the Moment of the Inertia of the mass is 0.5.
Radius of the Gyration = 25 cm.
Using the Formula,
Moment of the Inertia = Radius of Gyration² × mass
∴ I = mr²
∴ I = 8 × 25 × 25 × 10⁻⁴
∴ I = 5000 × 10⁻⁴
∴ I = 0.5 Kgm⁻²
Hence, the Moment of the Inertia of the mass is 0.5.
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