a wheel of radius 1.5m is rotating anout its axis with an Amgular velocity in 60 rpm which the brakes are appied the wheel comes to rest in 10 sec. calculate the no. of revolution made by wheel before coming to rest. (assume that a is constant)
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Answer:
First, convert initial angular speed in rev/min to rad/s
60/π rpm = [(60/π) × 2 π rad]/(60 s) rad/s = 2 rad/s
ωf = ωi + αt
= 2 rad/s + (10 rad/s² × 2.0 s)
= 22 rad/s
Angular speed at t = 2.0 second is 22 rad/s
θ = (ωf² - ωi²) / (2 × α)
= [(22 rad/s)² - (2 rad/s)²] / (2 × 10 rad/s²)
= 24 rad
Angular displacement covered by wheel after 2.0 second is 24 rad
Explanation:
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