A wheel of radius 10cm can rotate freely about its centre .A string is wrapped over its rim and is pulled by a force of 5.0N. it is found that the torque produces an angular acceleration 2.rad/s² in the wheel . calculate the moment of inertia of the wheel .
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Solution : The force acting on the wheel are (2) W dur to gravity , (2) N due to the support at the centre and (3) F due to tension . the torque of W and N are separately zero and that of F is F.r . The net torque is
Torque = (F).(r)
T = (5.0 N) (10cn) = 0.50N-m
The moment of inertia
= Torque /angular acceleration
= 0.50/2 = 0.24 kg-m² Answer ✔
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Torque = (F).(r)
T = (5.0 N) (10cn) = 0.50N-m
The moment of inertia
= Torque /angular acceleration
= 0.50/2 = 0.24 kg-m² Answer ✔
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