A wheel of radius 20 cm has forces applied to it as shown in the figure. The torque
p
forces 4 N at A, 8 N at B, 6 N at C, 9 N at D at angles indicated is:
(a) 5.4 N-m anticlockwise
(c) 2.0 Nm clockwise
(b) 1.80 N-m clockwise
(d) 5.4 N-m clockwise
Answers
The torque in the direction is 1.8 N-m c.
Explanation:
Force 8 N can also be resolved into two components.
- Tangential direction
- Radial directions
τnet = [ 9+8 sin(30°) − 4] [0.2) N-m clockwise
The torque produced by the forces 9 N at D is
τ = 9 N x sin 90° x 0.2 = 1.8 N-m (by using the equation (1) and substituting corresponding values from the figure)
In the clockwise direction.
So Total torque is
τ = 0.8−0.8−1.8=−1.8
= 1.8 N-m c
Thus the torque in the direction is 1.8 N-m c.
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