Question

A wheel of radius R rolls on the ground with a uniform velocity v. The relative acceleration of topmost point of the wheel with respect to the bottommost point is:

Answer 1

Answer:

relative acceleration of the top point with respect to bottom point is

$a_{12} = \frac{2v^2}{R}$

Explanation:

Since we know that wheel is rolling with uniform speed

So acceleration of the top most point of the wheel is given as

$a_1 = \frac{v^2}{R}$ downwards

Similarly the acceleration of the bottom most point of the wheel is given as

$a_2 = \frac{v^2}{R}$ upwards

now the relative acceleration of the top most point with respect to bottom point is given as

$a_{12} = a_1 - a_2$

$a_[12} = \frac{v^2}{R} - (-\frac{v^2}{R})$

$a_{12} = \frac{2v^2}{R}$

#Learn

topic : Rolling motion

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