A wheel starts rotating from rest with angular acceleration of 2 rad per second square till its angular speed becomes 6 rad per second. The angular displacement of the wheel will be equal to
Answers
Answered by
0
ANSWER
If θ be the angular displacement, then θ=
2
1
αt
2
=0.5(2)(10)
2
=100 radians (using equation : S=ut+1/2at
2
)
Thus, number of revolutions =
2π
θ
=
2π
100
=15.92∼16
If θ be the angular displacement, then θ=
2
1
αt
2
=0.5(2)(10)
2
=100 radians (using equation : S=ut+1/2at
2
)
Thus, number of revolutions =
2π
θ
=
2π
100
=15.92∼16
Answered by
1
ANSWER
If θ be the angular displacement, then θ=
2
1
αt
2
=0.5(2)(10)
2
=100 radians (using equation : S=ut+1/2at
2
)
Thus, number of revolutions =
2π
θ
=
2π
100
=15.92∼16
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