A wheel turning with angular speed 40 rev/s is brought to rest with a constant acceleration.It turns 60 rev before it stops. What time (in s) elapses before it stops?
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Answer:
given = speed = 40rev/s
constant accelaration = 60rev
to find = time=?
solution =
w =40rev/s
θ = 60rev
w²= w₁² - 2∝θ
wf = 0
0²= 1600rev/s² -2 X ∝ X 60 rev
∝ = 1600/120Rev/ s²
∝ = 13.33
wf = wi - ∝t
wi = 30rev/s
t = wi - wf / ∝
t = 30 / 13.33
t = 2.25 sec
time (in s) elapses before it stops is t = 2.25 sec
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