Question

a wheel with 100 metallic spokes each 0.5 m long is rotated with a speed of 120 rev/min in a plane normal to the horizontal component of earths magnetic field if the resultant magnetic field at that plane is 4x10^-4 T and the angle of dip is 30 degree then find the emf induced bw the axle and the rim of the wheel​

Answer 1

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Answer 2

The emf produced between the axle and the rim of the wheel is 5.4 x 10⁻⁴ V

Given:

Number of Spokes (N) = 100

Length of each spoke (L) = 0.5cm

Magnetic field (B) = 4 x 10⁻⁴T

Frequency (f) = 120rpm = 2rps

Angle of dip(δ) = 30°

To Find:

The emf produced between the axle and the rim of the wheel

Solution:

ω = 2πv = 4π

e =1/2 (Bωl²)

e = 1/2(4 x 10⁻⁴ x 4π x 0.5 x0.5)

e = 1/2(16π x 10⁻⁴ x 0.25)

e = 1/2(4π x 10⁻⁴)

e = 2π x 10⁻⁴

e = 5.4 x 10⁻⁴ V

Therefore, the emf induced between the axle and the rim of the wheel when the angle of dip is 30° is 5.4 x 10⁻⁴ V

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