A wheel with 6 equal parts has 2 parts with single dots. 1 part with 2 dots, 1 part with and 2 parts with no dots. What is the probability that after spinning the wheel, the arrow will come to the rest of the following parts.
(i). Part with a single dot
(ii). Part with 2 dots
(iii). Part with 3 dots
(iv). Part with no dots
Answers
Given : A wheel with 6 equal parts has 2 parts with single dots. 1 part with 2 dots, 1 part with and 2 parts with no dots.
To Find : probability that after spinning the wheel, the arrow will come to the rest of the following parts.
(i). Part with a single dot
(ii). Part with 2 dots
(iii). Part with 3 dots
(iv). Part with no dots
Solution:
n(S) = 6
A = Part with a single dot
n(A) = 2
P (A) = 2/6 = 1/3
B = Part with two dots
n(B) =1
P (B) = 1/6 = 1/6
C = Part with three dots
n(C) =1
P (C) = 1/6 = 1/6
D = Part with no dots
n(D) = 2
P (D) = 2/6 = 1/3
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Answer:
Given : A wheel with 6 equal parts has 2 parts with single dots. 1 part with 2 dots, 1 part with and 2 parts with no dots.
To Find : probability that after spinning the wheel, the arrow will come to the rest of the following parts.
(i). Part with a single dot
(ii). Part with 2 dots
(iii). Part with 3 dots
(iv). Part with no dots
Solution:
n(S) = 6
A = Part with a single dot
n(A) = 2
P (A) = 2/6 = 1/3
B = Part with two dots
n(B) =1
P (B) = 1/6 = 1/6
C = Part with three dots
n(C) =1
P (C) = 1/6 = 1/6
D = Part with no dots
n(D) = 2
P (D) = 2/6 = 1/3
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