Question

A wheel with a radius of 5 cm is placed inside another wheel with a radius of 28 cm. The smaller wheel rolls inside the fixed bigger wheel. The point
P, on the smaller wheel starts at the point P on the bigger wheel. After how many revolutions of the smaller wheel do the points P and
P, coincide again?

Please answer it fast, I'll give 50 points and Brainliest answer!

Answer 1

Answer:

Given :  r=5cm=0.05m

The angle of rotation       ϕ=A+Bt+Ct  

2  +Dt  3

 

Angular acceleration       α=  dt  2 d  2 ϕ

​

=2C+6Dt                

 where C is a constant

∴  Change in angular acceleration per second      Δα=6D=(6)(1)=6  rad/s  2

 

Thus Change in tangential acceleration     Δa  

t =rΔα ⟹   Δa  

t  =0.05×6=0.3  ms  −2

Step-by-step explanation:

Answer 2

Answer:

Given : r=5cm=0.05m

The angle of rotation ϕ=A+Bt+Ct^2 +Dt ^3

Angular acceleration α= dt^2

d 2ϕ

=2C+6Dt

where C is a constant

∴ Change in angular acceleration per second Δα=6D=(6)(1)=6 rad/s

2

Thus Change in tangential acceleration Δa= 6D

=rΔα

⟹ Δat

=0.05×6=0.3 ms

−2