Question

A wheelbarrow has a mechanical advantage of 2.4.what effort is required to lift a load of 120 N ?​

Answer 1

Effort arm length = 288 N

Explanation:

Given,

Mechanical advantage (MA) = 2.4, load arm length = 120N and

effort arm length =?

Mechanical advantage (MA) = $\frac{ effort arm length}{load arm length}$

∴ Effort arm length =  Mechanical advantage (MA)  × Load arm length

⇒ Effort arm length = 2.4 × 120N = 288 N

Hence, Effort arm length = 288 N

Answer 2

The effort is 288 N.

Explanation:

Given that,

Mechanical advantage = 2.4

Load = 120 N

We need to calculate the effort

Using formula of mechanical advantage

$Mechanical advantage = \dfrac{effort\ arm\ length}{load\ arm</p><p> length}$

$effort\ arm\ length =Mechanical\ advantage\times load\ arm\ length$

Put the value into the formula

$effort\ arm\ length=2.4\times120$

$efffort\ arm\ length=288\ N$

Hence, The effort is 288 N.

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Topic : mechanical advantage

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