Question

a When a force of 3N was applied on a body, it was displaced by 12m in the direction of application of force. Then the work done will be equal to
(a) (12x3) Joule (b) (12+3) Joule Sito (c) (12/3) Joule (d) (12–3) joule​

Answer 1

Answer:

a) 12 × 3 joules

Explanation:

we know that work = force × displacement

in this case force is 3 N and displacement is 12 m so work done will be ( 3× 12 ) N m or ( 3 × 12 ) Joules.

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Answer 2

Given data : A force of 3N was applied on a body, it was displaced by 12m in the direction of application of force.

Solution : A/C to given data;

• Force = 3 N
• Displacement = 12 m

Definition of work done : We know energy can neither be formed nor be demolished, so the energy must be converted into some other form. So, Work is the energy transferred to or from an object via the application of force along a displacement.

∴ Work done = force × displacement

Now,

➜ Work done = force × displacement

➜ Work done = 3 × 12

➜ Work done = 36 joule

Answer : Hence, work done by force acting on a body is 36 joule. {Ans. (12 × 3) joule}.

More info :

• Work has only a magnitude but no direction. The formula for work is written as a dot product of force and displacement.
• Force is stated as a vector quantity, meaning it has elements of both magnitude and direction.
• Displacement is an example of a vector quantity.
• A vector is any quantity with both magnitude and direction

Formula :

• Work done but a force acting on a body, W = F • s = Fs cos θ

where,

• W = work done
• F = force
• s = displacement
• cos θ = the cosine of the angle θ between them

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