a) Which bulb has lesser resistance; 100 W, 220 V or 60 W, 220 V?
Find the value of potential difference or voltage drop across
6 ohm resistor, in given figure:
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Answer:60 whatt
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P1= 100W , V= 220V , P2= 60W , V=220V
P=V^2/R
=>. R=V^2/P
Case -1
R1 = 220 x 220/100
Therefore, R1= 484 ohm
Case-2
R2 = 220 x 220/ 60
Therefore, R2= 806.66 ohm or 806.67 ohm
There fore, the bulb with the power (P1) 100W and potential difference 220V has lesser resistance (R1) then the other bulb with power 60W.
P=V^2/R
=>. R=V^2/P
Case -1
R1 = 220 x 220/100
Therefore, R1= 484 ohm
Case-2
R2 = 220 x 220/ 60
Therefore, R2= 806.66 ohm or 806.67 ohm
There fore, the bulb with the power (P1) 100W and potential difference 220V has lesser resistance (R1) then the other bulb with power 60W.
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