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a) Which bulb has lesser resistance; 100 W, 220 V or 60 W, 220 V?

Find the value of potential difference or voltage drop across

6 ohm resistor, in given figure:

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## Answers

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Answer:60 whatt

Exp anation:

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P1= 100W , V= 220V , P2= 60W , V=220V

P=V^2/R

=>. R=V^2/P

Case -1

R1 = 220 x 220/100

Therefore, R1= 484 ohm

Case-2

R2 = 220 x 220/ 60

Therefore, R2= 806.66 ohm or 806.67 ohm

There fore, the bulb with the power (P1) 100W and potential difference 220V has lesser resistance (R1) then the other bulb with power 60W.

P=V^2/R

=>. R=V^2/P

Case -1

R1 = 220 x 220/100

Therefore, R1= 484 ohm

Case-2

R2 = 220 x 220/ 60

Therefore, R2= 806.66 ohm or 806.67 ohm

There fore, the bulb with the power (P1) 100W and potential difference 220V has lesser resistance (R1) then the other bulb with power 60W.

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