Question

a) Which bulb has lesser resistance; 100 W, 220 V or 60 W, 220 V?
Find the value of potential difference or voltage drop across
6 ohm resistor, in given figure:​

Answer 1

Answer:60 whatt

Exp anation:

Answer 2

P1= 100W , V= 220V , P2= 60W , V=220V

P=V^2/R

=>. R=V^2/P

Case -1

R1 = 220 x 220/100
Therefore, R1= 484 ohm

Case-2

R2 = 220 x 220/ 60
Therefore, R2= 806.66 ohm or 806.67 ohm

There fore, the bulb with the power (P1) 100W and potential difference 220V has lesser resistance (R1) then the other bulb with power 60W.