Science, asked by sourav2615, 11 months ago

a) Which element will form a divalent cation?

b) Write the formula of the compound formed by the reaction between A and D.

c) How many bonds are present in the molecule R2.?Name the type of bond present in this

molecule ?

Answers

Answered by yadashishrao123
1

Answer:from this question c will show divalent catinatin

Explanation:

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Answered by ChitranjanMahajan
2

Please Note - The missing table in the question has been attached below.

SOLUTION :

(A) The element 'B' will form a divalent cation.

(B) The formula of the compound formed by the reaction between 'A' and 'D' is A₂D.

(C) There are three bonds present in the molecule R₂, which are covalent in nature.

(A) A divalent cation is of the form M²+, where M is a metal.

• Now, according to the periodic trend, the elements belonging to group I and group II in the periodic table are highly metallic in nature, and their valency is equal to their respective group numbers.

• So, the element 'B' belonging to group 2 in the periodic table will have a valency of +2, forming a divalent cation.

(B) A bond is formed by the transfer or sharing of valence electrons between two elements to attain octet in each of them.

• Element 'A' belongs to group 1 in the periodic table. So, it has 1 electron in its valence shell.

• For element A, it is easier to lose its 1 valence electron to attain stability rather than gaining 7 more electrons to attain octet.

• The element 'D' belongs to group 16 the periodic table. So, the number of electrons in its valence shell is equal to 16 - 10 = 6.

• For element D, it is easier to gain 2 electrons to complete its octet rather than losing all 6 of its valence electrons for attaining the same.

• Therefore, when 'A' and 'D' are reacted, A readily loses its 1 extra electron, which is gained by 'D'.

• Now, D needs 2 e- in total to attain octet. Therefore, 'D' reacts with two atoms of 'A', forming a compound of the formula A₂D.

(C) The element 'R' belongs to group 15 in the periodic table. So, its number of valence electrons is 15 - 10 = 5.

• An element with 5 valence electrons can neither gain nor lose electrons. It can only share its valence electrons.

• In order to be stable, each R atom needs to acquire 3 more electrons in its valence shell to complete its octet.

• So, two atoms of R share 3 valence electrons each with one another, so that they both have 5 + 3 = 8 electrons in their valence shell. This results in the formation of an R₂ molecule.

• Since three electrons are shared by each atom of R, three bonds are present in the R₂ molecule.

• A bond which is formed by the sharing of electrons is called a covalent bond. Therefore, the bond in R₂ molecule is covalent in nature.

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