Physics, asked by padisettisivakumari, 10 months ago

A whistle giving out 450Hz approaches a stationary observer at a speed of 33m/s . The frequency heard by the observer in Hz is

Answers

Answered by praveen2007h

5

Answer:

Explanation:

Source is moving towards the observer

f′=f(vv−vs)=450(330330−33)

f′=500Hz

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