Physics, asked by Deepak7615, 1 year ago

A whistle S of frequency f revolves in a circle of radius R at a constant speed v. What is the ratio of largest and smallest frequency detected by a detector D at rest at a distance 2R from the centre of circle as shown in figure? (take c as speed of sound)(a) (\frac{c+v}{c-v})(b) \sqrt{2}(\frac{c+v}{c-v})(c) √2(d) \frac{(c+v)}{c\sqrt{2}}

Answers

Answered by abhi178
6

answer : option (a) \left(\frac{c+v}{c-v}\right)

Largest frequency will be detected when the source approaches detector along the line joining.

according to Doppler's effect,

e.g., largest frequency is given by,

f_2=\left(\frac{c}{c-v}\right)f

where v is speed of source (whistle )

c is speed of sound and f is initial frequency.

and the smallest frequency will be detected when the source recedes the detector along the line joining

according to Doppler's effect ,

e.g., smallest frequency is given by,

f_1=\left(\frac{c}{c+v}\right)f

now, ratio of largest and smallest frequency , \frac{f_2}{f_1}=\left(\frac{c+v}{c-v}\right)

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