Question

A white of sn(oh)4is peptized with dil. Hcl the sol particle will carry

Answer 1

Picture of reaction: img1  BB  html

Сoding to search: SnOH4 + 4 HCl = SnCl4 + 4 H2O

Add / Edited: 04.10.2014 / 02.02.2015

Evaluation of information: 5.0 out of 5 / number of vo

Source: https://chemiday.com/en/reaction/3-1-0-668

Answer 2

Answer:

Concept:

Precipitation in an aqueous solution is the transformation of a dissolved component into an insoluble solid from a super-saturated solution. The precipitate is the solid that forms. In an inorganic chemical process that results in precipitation, the precipitant is the chemical substance that causes the solid to develop. The clear fluid that persists above the precipitate or centrifuged solid phase is known as the'supernate' or'supernatant.' When solid impurities segregate from a solid phase, the concept of precipitation can be extended to other disciplines of chemistry (organic chemistry and biology) and even to solid phases.

Given:

A white of sn(oh)4is peptized with dil. Hcl the sol particle will carry

Find:

write the Hcl the sol particle will carry

Answer:

The answer is positive charge

Hydrated $Sn0_{2}$ forms $Sncl_{4}$ with $HCL.Sn4_{4+}$ adsorb as $Sn0_{2}$ particles to form positive sol.

$Sn(OH)_{4} +4HCl- > SNCl_{4} +4H_{2} 0 and[S_{n}OH_{4} ]Sn^{4^{+} } ,4Cl^{-}$  

(Positive charge)

=> When the concentration of a substance exceeds its solubility, it can precipitate. This can happen as a result of temperature fluctuations, solvent evaporation, or solvent mixing. A solution that is significantly supersaturated precipitates more quickly. A chemical reaction can result in the development of a precipitate. A white precipitate of barium sulphate is created when a barium chloride solution combines with sulphuric acid. A yellow precipitate of lead(II) iodide is generated when a potassium iodide solution combines with a lead(II) nitrate solution.