Question

a white pool ball of mass 1.0kg moving at 10m/s collides with a 1.2 kg red pool ball continues in the same direction with a velocity of 3.0m/s. neglecting friction, the velocity of the ball after the collision is ___ m/s. round to the nearest tenth

Answer 1

Answer :

v of the ball after collision = 0.6 m/s  

$\rule{100}2$

Given :

For white ball,

• $\sf Mass_1 = 1 kg$
• $\sf u_1 = 10 m/s$

For Red pool ball,

• $\sf Mass_2 = 1.2 kg$
• $\sf u_2 = 3 m/s$

We've to find final velocity of red pool ball.

We know that,

$\sf M_1 U_1 + M_2 U_2 = M_1 V_1 + M_2 V_2$

Substitute the given values.

$\sf\implies 1\times 10 = 1.2\times 3 = V(1+1.2)$

$\sf\implies 10+3.6 = V+1.2V$

$\sf\implies 13.6 = 2.2 V$

$\sf\implies V=\dfrac{13.6}{2.2}$

$\sf\implies V=\dfrac{1360}{2200}$

$\sf\therefore V=0.6$

Answer : The velocity of the ball after collision is 0.6 m/s.