A white presipitate can be obtained by adding dilute sulphuric acid to
A.cuso4
B.nacl
C.bacl2
D.na2so4
Answers
Answered by
52
BaCl2 is the answer (option c)
Equation : H2SO4 + BaCl2 ——> BaSO4 + 2HCl
Here, BaSO4 is the white precipitate.
Hope this helps ya
Equation : H2SO4 + BaCl2 ——> BaSO4 + 2HCl
Here, BaSO4 is the white precipitate.
Hope this helps ya
Answered by
24
Answer: A white precipitate can be obtained by adding dilute sulphuric acid to (C). BaCl2
Explanation:
When dilute sulphuric acid reacts with the barium chloride then the barium sulphate is formed as a product with hydrochloric gas.
The reaction is
BaCl2 + H2SO4 → BaSO4 + 2HCl
The barium sulphate so formed is an insoluble white precipitate. Barium chloride does not reacts with the hydrochloric acid as both consists of the negative anions.
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