Math, asked by animaza51, 1 year ago


A white rectangular board 28 cm long and 16 cm wide is placed in the
centre of a large rectangular wooden board. It creates a border of 2 cm
around it. Find the area not covered by the white board.​

Answers

Answered by Krutivedansh
12

Step-by-step explanation:

L of white board=28cm

B=16cm

L of wooden board=28+2=30cm

B=16+2=18cm

Area of small rectangle=lxb

=28x16

=448cm

Area of big rectangle=30x18

=540cm

Area of border=540-448

=92cm

Hope it helps u

Please mark me as brainliest n

Plzzz follow me

Answered by FelisFelis
10

The area not covered by the white board is 192 cm².

Step-by-step explanation:

Consider the provided information.

A white rectangular board 28 cm long and 16 cm wide.

Area of rectangle is: A=Length\times Width

Substitute the respective values

Area of White Board is:

A=28\times 16=448

The area of white board is 448 cm²

Wooden board creates a border of 2 cm around it.

Wooden Board dimension is: (28 + 2 + 2) cm long and (16 + 2 + 2) cm wide

Wooden Board dimension is: 32 cm long and 20 cm wide.

The are of Wooden board is:

A=32\times20=640

The area not covered by the white board is:

640 cm² - 448 cm² = 192 cm²

The area not covered by the white board is 192 cm².

#Learn more

A rectangle has 25cmas its length and 250 square cm as its area.if the area is increased to 1 1/4 times the original area by increasing its length only, then the perimeter will be

https://brainly.in/question/12462853

Similar questions