A white solid “X” when reacts with an acid “B” in its dilute solution produces a gas which turns lime water milky. Identify “A” and “B”, and write the two equations involved. No spamming! Else report!
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Answer:
the white solid is zinc carbonate
znco3+ 2hcl-zncl2+h2O+co2
thus acid is hcl
gas liberated is co2
and co2 turns lime water milky
co2+ca(OH)2 - caco3+h2O
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Answer:
3)The white solid “X” is probably ZnCO3 (or CaCO3)
The acid “B” can be HCl (or H2SO4)
The gas is CO2
reactions----->ZnCO3(white,solid)+2HCl(aq.)-->ZnCl2(aq.)+CO2(g)+H2O(l)
OR CaCO3(white,solid)+2HCl(aq.)-->CaCl2(aq.)+ CO2(g)+H2O(l)
ii) Ca(OH)2 (aq.)+CO2(g)--> CaCO3 +H2O
(lime water) (white precipitate)
Explanation:
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