Question

A whole number is added to 405 and the same number is subtracted from 405. The sum of

the resulting numbers is (1 mark)

A. 0 B. 725

C. 850 D. 81​

Answer 1

Answer:

answer for the given problem is given

Answer 2

$Let \: a \:whole\: number \:be \: \pink{x}$

$x \:is \: added \: to \: 405 = 405 + x \: --(1)$

$and \: x \:is \: subtracted \: from\: 405 = 405 - x \: --(2)$

/* According to the problem given */

$The \: sum \:of \:the \: resulting \: numbers$

$=( 405 + x ) + ( 405 - x )$

$= 405 +\cancel { x} + 405 - \cancel {x}$

$= 405 + 405$

$= 810$

Therefore.,

$\red{ The \: sum \:of \:the \: resulting \: numbers}$

$\green { = 810}$

$\red{ Given \: options \:are \:wrong .}$

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