Math, asked by aman121105, 1 month ago

A wholesaler bought walnuts and cashew. The price of walnuts per kg being thrice that of cashew per kg. He then sold 9kg of cashew at profit of 10% and 18kg of walnuts at a profit of 22% to a local shopkeeper. The shopkeeper saved 6kg of walnuts and 3kg of cashew for future use and sold the remaining mixture at Rs. 170 per kg thus making profit of 25%

At what price did the wholesaler bought the cashew ?​

Answers

Answered by sirapanasettynavyasr
0

Step-by-step explanation:

The price of walnut per kg being thrice that of peanut per kg will be 3p.

8 kg of peanuts would cost him 8p. Now since he sold the 8 kg of peanuts at a 10% profit, he earned 110%(8p) => 11/10 (8p) => 88p/10.

Similarly 16 kg of walnuts would cost him 48p, and since he sold them at a 20% profit, he earned 120% (48p) => 6/5 (48p) => 288p/5

The shopkeeper who bought the products from the wholesaler lost some of the product in transit; therefore he was finally left with 11 kg of walnuts and 5 kg of peanuts. He then mixed the remaining nuts, and this brought the total quantity to 16 kg.

The shopkeeper's per kg price is $166 => Total amount earned by shopkeeper for 16 kg = 16 * 166 => 2656.

Now since the shopkeeper made a profit of 25% on his entire purchase of 8 kg of peanuts and 16 kg of walnuts = 125%(88p/10 + 288p/5)

And this 125%(88p/10 + 288p/5) is equal to 2656

5/4(88p/10 + 288p/5) = 2656

=> p = 32.

Since the price of walnut per kg is 3p.

Therefore, 3*32 = 96.

Answer: D

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