Question

A wicket keeper catches a ball moving at 30 m/s. if he moves his hand as the ball is caught so that it comes to rest over 10 cm what is its acceleration ​

Answer 1

Answer:

900 = a/5

a= 900 ×5

= 4500m/s²

Answer 2

Answer:

.

Explanation:

V1 = 0

v2 = 30 m/ s

d = 10 cm

Acceleration = (change in velocity)/(change in

time) a = Δv ÷ Δt

30/ 10

3 m/ s²