Question

a wicket keeping glove is dropped from a height of 40m and simultaneously a ball is thrown upward from the ground with a speed of 40m/s. when and where do they meet?

Answer 1

Given:

Height = 40 m

Speed = 40 m / s

To find:

The time and the height that they meet.

Solution:

By laws of motion,

Gloves downward motion,

Height = Initial velocity * Time + 1 / 2 * Gravity * Time^2

Initial velocity = 0

Hence,

Height = 1 / 2 * Gravity * Time^2

Gravity = 9.8 m / s

Height = 4.9 Time^2

Ball upward motion,

Initial velocity = 40

Hence,

40 - Height = 40 * 1 / 2 * 9.8  * Time^2

Solving for Time,

Time = 1 s

Then,

We get,

Height = 4.9 m

The meeting height = 40 - 4.9

The meeting height = 35.1 m

Hence, The glove will meet the ball at 35.1 m above the ground after 1 s.

Answer 2

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