Question

a wicketkeeper gloves dropped from a hieght of 4o metres and simultaneously a ball is thrown upward from a ground with a speed of 40 metres so when and where do they meet


please give solution fast​

Answer 1

Answer:

Height = 40 m

Speed = 40 m / s

To find:

The time and the height that they meet.

Solution:

By laws of motion,

Gloves downward motion,

Height = Initial velocity * Time + 1 / 2 * Gravity * Time^2

Initial velocity = 0

Hence,

Height = 1 / 2 * Gravity * Time^2

Gravity = 9.8 m / s

Height = 4.9 Time^2

Ball upward motion,

Initial velocity = 40

Hence,

40 - Height = 40 * 1 / 2 * 9.8  * Time^2

Solving for Time,

Time = 1 s

Then,

We get,

Height = 4.9 m

The meeting height = 40 - 4.9

The meeting height = 35.1 m

Hence, The glove will meet the ball at 35.1 m above the ground after 1 s.