A Wife And Husband Attend An Interview. The Probability Of The Wife Getting Selected Is 1/3 And The Husband Is 1/4. Then The Probability Of At Least One Of Them Getting Selected Is
Answers
Answer:
The Probability of at least one of them getting selected is 5/12.
Step-by-step explanation:
Given:
Probability of getting wife select , P(W) = 1/3
Probability of getting husband select , P(H) = 1/4
To find: Probability of getting at least one of them selected.
Probability of at least one of them getting selected = P(H) × P(W') + P(H') × P(W)
P(W') represent probability of not getting wife select.
P(W') = 1 - 1/3 = 2/3
P(H') represent probability of not getting husband select.
P(H') = 1 - 1/4 = 3/4
Probability of at least one of them getting selected = 1/4 × 2/3 + 3/4 × 1/3
= 2/12 + 3/12
= 5/12
Therefore, The Probability of at least one of them getting selected is 5/12.