Question

A wind broke a tree and treetop strikes the ground 15m from its base. The broken part of the tree has a length of 20m. How high was the tree before it was broken?

Please I really need it :(

Answer 1

Solution:-

given :- A wind broke a tree and treetop strikes the ground 15m from its base. The broken part of the tree has a length of 20m.

hence,

Let A’CB be the tree before it broken at the point C and let the top A’ touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B.

AB = 20 m and BC = 15 m

Using Pythagoras theorem,

In ΔABC

(AC)²=(AB)²+(BC)²

(AC)²=(20)²+(15)²

(AC)²= 400 + 335

(AC)²=735

AC = √735 = 5*3

AC= 7√15 m

or 27.1108834234519 m

let, AC = 27m or 7√15 m

Hence, the total height of the

tree(A’B) = A’C + CB = 27 + 15 = 42m

or 7√15 + 15 = 22√15m

i hope it helps you.....