Question

A wind with speed 40 m/s blows parallel to the roof of a house. The area of the roof is 250 m2 . Assuming that the pressure inside the house is atmospheric pressure, the force exerted by the wind on the roof and the direction of the force will be (rair = 1.2 kg/m3 ) ​

Answer 1

Answer:

Applying Bernoulli's theorem to two points just inside the house and outside the house,

Applying Bernoulli's theorem to two points just inside the house and outside the house,P+21ρv2=constant

Applying Bernoulli's theorem to two points just inside the house and outside the house,P+21ρv2=constantInside the pressure is Patm

Applying Bernoulli's theorem to two points just inside the house and outside the house,P+21ρv2=constantInside the pressure is PatmThe pressure outside is P

Applying Bernoulli's theorem to two points just inside the house and outside the house,P+21ρv2=constantInside the pressure is PatmThe pressure outside is Pv is zero inside.

Applying Bernoulli's theorem to two points just inside the house and outside the house,P+21ρv2=constantInside the pressure is PatmThe pressure outside is Pv is zero inside.∴P−Patm=21ρv2=21×1.2×402=960

Applying Bernoulli's theorem to two points just inside the house and outside the house,P+21ρv2=constantInside the pressure is PatmThe pressure outside is Pv is zero inside.∴P−Patm=21ρv2=21×1.2×402=960Force is : F=(P−Patm)×Area=960×250=2.4×105N in upward direction as pressure goes from higher to lower pressure area.

Explanation:

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