Question

A window is in the shape of a rectangle surmounted by a semicircle. If the perimeter of the window is 20ft.find the maximum area

Answer 1

Answer:

Step-by-step explanation:

Suppose the dimension of rectangle is =  a*a;

so the radius of semicircle is  = a/2;

Now perimeter of semicircle = pi * (a/2);

and the perimeter of another three sides is = 3a;

So total perimeter = 3a + pi * (a/2) = 20ft;

Now calculate the value of a;

a = 4.3;

Maximum area = area of rectangle + area of semicircle;

Max. Area = 4.3*4.3 + pi (4.3^2)/2 = 47.5 sq.ft