A window pane is in the shape of regular octagon. find the cost of polishing the window pane at $2.50perm²
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Pic hvae the solution
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bjustinbieber15:
Good bro, although you were very late, I tried it 2-3 times and solved it. This was a late answer but still I thank you for putting effort to answer this question
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A window pane is in the shape of regular octagon. The cost of polishing the window pane at $2.50perm² is $477.50.
To find the total area of the figure.
The octagon in the figure includes 2 trapeziums.
Each trapezium has a height 'h' of 5m , side of 'b' = 7m and another side 'a' = 13m.
So, the area of trapezium is given as (a+b)h × (1/2)
= (13+7) × 5 × (1/2) m^2
= 50 m^2
Total area of the 2 trapezium = 2 × 50 = 100 m^2.
There is a rectangle with length 'l' = 13m and breadth 'b' = 7m between the 2 trapeziums.
Its area is l × b = 13 × 7 = 91 m^2.
Hence, the total area of the figure = (100 + 91)m^2 = 191 m^2
Cost per m^2 = $2.50
So, cost of 191m^2 = $(2.50 × 191) = $477.50
Hence, the total cost is $477.50
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