Question

A wine and it's container is 6kg. After 3÷4 of the wine is consumed,the contaimer and remaining wine weigh 3 kg. What is the weight of the container?

Answer 1

2 kg

Solution:

Let the weight of wine be x kg and container be y kg.

$x + y = 6 \: \: \: (eqn \: 1)$

3/4th wine is consumed.

Wine left = 1/4 x kg

$= \frac{1}{4}x + y = 3 \: \: \: (eqn \: 2)$

Multiply eqn 2 by 4.

$x + 4y = 12 \: \: \: (eqn \: 3)$

Subtract eqn 1 from eqn 3.

$x + 4y - x - y = 12 - 6 \\ 3y = 6 \\ y = 2$

So, weight of container is 2 kg.