A wine seller had three types of wine. 403 liters of 1st kind, 434 liters of 2nd kind and 465 liters of 3rd kind. Find the least possible number of barrels/casks of equal size in which different types of wine can be filled without mixing.
Answers
Answer:
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Step-by-step explanation:
Factors of
403 = 13x31
434 = 2x7x31
465 = 5x3x31
HCF = 31.
The volume of the cans should be 31 litres, each. The minimum number of such cans is 42 of which 13 will be for the 1st wine, 14 for the 2nd wine and 15 for the 3rd wine.
Given : A wine seller had three types of wine.
403 liters of 1st kind,
434 liters of 2nd kind and
465 liters of 3rd kind.
To Find:
the least possible number of barrels/casks of equal size in which different types of wine can be filled without mixing
Solution:
403 liters of 1st kind,
434 liters of 2nd kind and
465 liters of 3rd kind.
Find the HCF to find max volume in a barrell/case can be filled
403 = 31 * 13
434 = 31 * 7 * 2
465 = 31 * 5 * 3
HCF = 31
least possible number of barrels/casks of equal size
= 403/31 + 434/31 + 465/31
= 13 + 14 + 15
= 42
42 barrels/casks of equal size
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