A wire 2 m long is hung at one end with a firm base. Hanging the weight on the other end of the wire increases its length by 2 cm, find the protrusion distortion that occurs in it.
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Answer:
Y=
Ax
FL
2×10
11
=
0.2×10
−4
x
48×2
extension=24×10
−6
m
Explanation:
One end of a wire 2 m long and 0.2 cm
2
in cross-section is fixed to a ceiling and a load of 4.8 kg is attached to the free end. Find the extension of the wire. Young's modulus of steel =2.0×10
11
N/m
2
. Take g=10 m/s
2
.
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