A wire 300 cm long and .625 sq. cm in cross – section is found to stretch 0.3 cm
under a tension of 1200 kilograms. What is the Young’s modulus of the material
of the wire?
Answers
Answered by
1
Answer:
Y = 18,816,000
Y = F.l/a.dl = 1200*9.8*300/0.625*0.3 = 18,816,000
Similar questions