Question

a wire 80 m long is cut into 2 bn pieces such that one part is greatter than other by 16m find length of each part​

Answer 1

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• Total length of wire = 80 m.

• The wire is cut in 2 parts.

• One is 16m more then another.

▪︎ Let the length of small part be x.

☆ ATQ,

$\sf\implies( 16m + x) + x = 80 m \\ \\ \sf\implies16m + 2x = 80m \\ \\ \sf\implies2x = (80 - 16)m \\ \\ \sf\implies2x = 64m \\ \\ \sf\implies \: x =\cancel \frac{64m}{2} \\ \\ \sf\implies \: x = 32 \: meter.$

${\large{\blue{\bold{\underline{Therefore,}}}}}$

☆ Smaller part = x = 32 meter.

☆ Larger part

= x + 16m.

= 32m + 16m.

= 48 meter.