Question

A wire 88 cm long bent into a circular loop is kept with plane of the coil perpendicular to the magnetic induction 2.5 Wb/m². Within 0.5 second, the coil is changed to a square and magnetic induction is increased by 0.5 Wb/m². Calculate the e.m.f. induced in the wire.
(Ans: 1.76 x 10⁻² V)

Answer 1

heya...

Here is your answer...

Length of the circular loop

L = 88 cmL=88cm

2\pi R = 882πR=88

R = 14 cmR=14cm

now area of the loop is given by

A = \pi r^2 = 616 cm^2A=πr2=616cm2

initial magnetic flux will be given by

\phi_1 = B.A = 0.0616 * 2.5 = 0.154 Wbϕ1​=B.A=0.0616∗2.5=0.154Wb

now when it is convert to square loop

area of the loop will be

A = L^2 = 0.22 * 0.22 = 0.0484 m^2A=L2=0.22∗0.22=0.0484m2

now final magnetic flux will be

\phi_2 = 0.0484* 3 = 0.1452 Wbϕ2​=0.0484∗3=0.1452Wb

Now as per Faraday's law EMF induced is given by

EMF = \frac{\phi_2 - \phi_1}{\Delta t}EMF=Δtϕ2​−ϕ1​​

EMF = \frac{0.154 - 0.1452}{0.5}EMF=0.50.154−0.1452​

EMF = 0.0176 VoltsEMF=0.0176Volts

So the induced EMF will be 0.0176 volts

It may help you....☺☺

Answer 2

Hey mate ^_^

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Answer:
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Length of the circular loop

L = 88
2 pi R = 88
R = 14 cm

Area of the loop is given by

A = 616 cm^2

Initial magnetic flux will be given by: 0.154 Wb

Square loop area of the loop will be: 0.0484 m^2

Final magnetic flux will be: 0.1452 Wb

Faraday's law EMF induced is given by (Check this attachment)

The induced EMF will be 0.0176 volts.

#Be Brainly❤️