Math, asked by ayush8667, 1 year ago

a wire a wire is bent in the form of a square of side 16.5 cm.it is straightened and then bent into a circle,what is thr the radius of the circle so formed ?

Answers

Answered by lakshay172u172
2
p=4*side
=4*16.5
=66cm^2
p of square= circumference of circle
66=2*pie*r
r=21/2 cm
plzz mark it brainliest
Answered by shreya32457
2
THANKS FOR THE QUESTION !

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GIVEN :

=> A WIRE IS BENT :

=> 1ST CONDITION :

=> IN A SQUARE SHAPE :

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THE DIMENSION OF THE SQUARE SHAPE :

=> SIDE :

=> 16.5 CM

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SO,

=> THE LENGTH OF THE WIRE :

=> PERIMETER OF THE SQUARE SHAPE

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PERIMETER OF A SQUARE :

=> 4 * SIDE

=> 4 * 16.5

=> 66 CM

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NOW,

=>[THE 2ND CONDITION :

=> THE WIRE IS STRAIGHTENED :

=> AND AGAIN BENT IN A CIRCULAR SHAPE :

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LENGTH OF WIRE :

=> CIRCUMFERENCE OF A CIRCLULAR SHAPED WIRE :

=> 66 CM

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CIRCUMFERENCE OF A CIRCLE :

=> 2 * π * R

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FROM THE INFO :

=> 2 * π * R = 66 CM

=> π * R = 66 / 2

=> 22 / 7 * R = 66 / 2

=> R = 66 * 7 / 2 * 22

=> R = 3 * 7 / 2

=> R = 21 / 2

=> R = 10.5 CM

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SO,

=> RADIUS :

=> ..................... 10.5 CM .....................

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HOPE IT WILL HELP U .......

THANKS AGAIN .........

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