Question

A wire along the x-axis carries a current of 3.50A in the negative direction. Calculate the force (expressed in term of unit vectors) on a 1.00cm sectioin of the wire exerted by these magnetic fiels. a. B=-(0.65T)hatj b. B=+(0.56T)hatk c. B=-(0.31T)hatj d. B=_(0.33T)hati-(0.28t)hatk e. B=+(0.74T)hatj-0(0.36T)hatk

Answer 1

Answer:

magnetic force = BVL

Explanation:

hope the answer will help you

Answer 2

The expression of force in the term of uni vectors are given below.

Explanation:

(a) F = i ( L x B )

F = 3.5 (0.01 i  x  - 0.65 j )

F = 3.5 (0.01 ) (0.65) (i x j) / k

F = 0.02275 k

(b) F =  i ( L x B )

F = 3.5 (0.01 i  x  +0.56 T k )

F = 3.5 (0.01 i  x  0.56 ( -i x k )

F = 0.196 j

(c) F = i ( L x B )

= 3.5 (0.01 i  x 0.31 T ( - i x -j)

F = .01085 k

(d) F = i ( L x B )

F = 3.5 ( 0.01 i  ) x ( - 33i - 0.28 t k)

F = 35 x 0.01 x 28 (-j)

F = 0.0098 j

(e) F =  i ( L x B )

F = 3.5 (0.01) x ( 74 j - 0.36 T k)

F = - k ( 0.0239 ) - j