Question

a wire bent in the form of a circle of radius 42 cm is again bent in the form of a square. what is the ratio of the region enclosed by the circle and the square

Answer 1

a wire is bent in the form of a circle of radius 42cm .
then, length of wire = circumference of circle
= 2πR
where R is the radius of the circle, e.g., R = 42cm

now, length of wire = 2 × 22/7 × 42 = 264 cm

now, again wire is bent in the form of a square .
perimeter of square = length of wire
4 × side length = 264
side length = 66 cm
so, area of square = (66)² cm²

and area of circle = πr² = 22/7 × 42 × 42
= 22 × 6 × 42 cm²

now, ratio of the area enclosed by the circle and the square = (22 × 6 × 42)/66 × 66
= 2 × 42/66 = 14/11

Answer 2

Step-by-step explanation:

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