Question

A wire bent in the form of a square of side 30 cm is bent in the form of a rectangle with length 35 cm find width of the rectangle.
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Answer 1

Answer:

Answer:

Step by step solution :STEP1:Equation at the end of step 1 (22m2 - 24m) + 36 = 0 STEP2:STEP3:Pulling out like terms

3.1 Pull out like factors :

4m2 - 24m + 36 = 4 • (m2 - 6m + 9)

Trying to factor by splitting the middle term

3.2 Factoring m2 - 6m + 9

The first term is, m2 its coefficient is 1 .

The middle term is, -6m its coefficient is -6 .

The last term, "the constant", is +9

Step-1 : Multiply the coefficient of the first term by the constant 1 • 9 = 9

Step-2 : Find two factors of 9 whose sum equals the coefficient of the middle term, which is -6 .

-9 + -1 = -10 -3 + -3 = -6 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and -3

m2 - 3m - 3m - 9

Step-4 : Add up the first 2 terms, pulling out like factors :

m • (m-3)

Add up the last 2 terms, pulling out common factors :

3 • (m-3)

Step-5 : Add up the four terms of step 4 :

(m-3) • (m-3)

Which is the desired factorization

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PeeyushVerma

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Explanation:

Given :-

wire the shape of sq..of side=30cm

To formed a rectangle

Solve= In both cases area will be same

Area of sq.=Area of rectangle

30×30=w×35

w=30×30/35

w=900/35

w=25.71.

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Answer 2

SOLUTION :

• Perimeter of square = Perimeter of rectangle
• Perimeter of square = 4 × side
• Perimeter = 4 × 30
• Perimeter = 120
• Perimeter of rectangle = 120 cm

Perimeter of rectangle = 2(Length + Breadth)

• 120 = 2×(35 + x)
• 120 = 70 + 2x
• 120 - 70 = 2x
• 50 = 2x
• 50/2 = x
• x = 25

★Width of rectangle is 25 cm