A wire bent in the form of a square of side 30 cm is bent in the form of a rectangle with length 35 cm find width of the rectangle.
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Answers
Explanation:
Given :-
wire the shape of sq..of side=30cm
To formed a rectangle
Solve= In both cases area will be same
Area of sq.=Area of rectangle
30×30=w×35
w=30×30/35
w=900/35
w=25.71.
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Answer:
Step by step solution :STEP1:Equation at the end of step 1 (22m2 - 24m) + 36 = 0 STEP2:STEP3:Pulling out like terms
3.1 Pull out like factors :
4m2 - 24m + 36 = 4 • (m2 - 6m + 9)
Trying to factor by splitting the middle term
3.2 Factoring m2 - 6m + 9
The first term is, m2 its coefficient is 1 .
The middle term is, -6m its coefficient is -6 .
The last term, "the constant", is +9
Step-1 : Multiply the coefficient of the first term by the constant 1 • 9 = 9
Step-2 : Find two factors of 9 whose sum equals the coefficient of the middle term, which is -6 .
-9 + -1 = -10 -3 + -3 = -6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and -3
m2 - 3m - 3m - 9
Step-4 : Add up the first 2 terms, pulling out like factors :
m • (m-3)
Add up the last 2 terms, pulling out common factors :
3 • (m-3)
Step-5 : Add up the four terms of step 4 :
(m-3) • (m-3)
Which is the desired factorization