Question

A wire bent in the form of an equilateral triangle encloses an area of 49√3 cm2. find the area enclosed by the same wire bent to form:
I)A square
ii)A rectangle whose breadth is 2cm less than it's length​

Answer 1

Step-by-step explanation:

the side of the triangle be a cm, then

S=

4

a

3

3

or a

2

=

3

4S

and the perimeter of the triangle = 3a

∴Circumference of the circle = 3a

∴ If r be the radius of the circle, 2πr=3a

∴r=

2π

3a

∴ Area of the circle =πr

2

=π×

4π

2

9a

2

=

4π

9

×

3

4S

=

π

3

3

S