a wire bent in the shape of a square with side 11 cm was straigthened out and bent in the shape of a circle find the radius and area covered by the circle
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We know that Area of a square is (side)^2 , area= 11 * 11 = 121 and area of square and are of circle be same and radius is pir^2= 121 means radius is √38.5
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side of square =11cm
perimeter of square =11×4=44cm
Therefore, length of wire = 44cm
So, circumference= 44cm
2pir=44cm
2×3.14×r =44cm
6.28 × r = 44cm
r =44÷6.28
r =4400÷628
radius = 7.01 cm
area = 3.14 ×7.01×7.01
=154.29cm^2
perimeter of square =11×4=44cm
Therefore, length of wire = 44cm
So, circumference= 44cm
2pir=44cm
2×3.14×r =44cm
6.28 × r = 44cm
r =44÷6.28
r =4400÷628
radius = 7.01 cm
area = 3.14 ×7.01×7.01
=154.29cm^2
raji22:
thank you sir
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