Math, asked by kmldhaliwal28, 1 year ago

A wire bent in the shape of rectangle of side 13.5 cm by 6.5cm was straightened and rebent into a square. Find the area of the square formed?

Answers

Answered by ShuchiRecites
20
Editing answer
Perimeter of rectangle= 2( length + breadth)
= 2(13.5+6.5)m
= 40m
As per question:
Perimeter of recatangle= Perimeter of square= 40cm
Perimeter of square= 4× side
40cm/4= side
10cm= side
Area of square = 10cm×10cm= 100cm^2
Thanks to rose who gave me chance to edit answer.


Anonymous: no sorry it's ok
Anonymous: but u understand, thanks
ShuchiRecites: kya mai edit kar skati hoo
Anonymous: yeah
Anonymous: u can
ShuchiRecites: galti hogayi reaaly sorry for arguement
ShuchiRecites: aap bahut aache ho apne mera answer report nahi kiys
Anonymous: no no, it's ok yar
Anonymous: and thank you
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Answered by Anonymous
15
hello!!

here's ur answer...

given:-

length of the rectangle=13.5cm

breadth of the rectangle=6.5cm

thus, perimeter of the rectangle=2(l+b)

=2(13.5+6.5)

=2×20

=40cm

perimeter of rectangle=perimeter of square

therefore perimeter of square=40m

4×side=40m

side=40/4

side=10cm

hence, area of the square=side×side

=10×10

=100cm²

hope this helps...

kmldhaliwal28: Thanks
Anonymous: ur most wlcm
Anonymous: and thank you very much for brainliest
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