Question

a wire bent in the shape of rectangle with side 12 and 10 cm is straightened out and bent in the shape of a circle . find the radius and area of the circle

Answer 1

Perimeter is
$2(12 + 10 )= 44$
Perimeter equals length of wire equals circumference
So
Let the radius be x
ATP
$2 \times \pi \times x = 44 \\ \pi \times x = 22 \\ x = \frac{22}{\pi}$
So area is
$\pi \times \frac{22}{\pi} \times \frac{22}{\pi} \\ = 22 \times \frac{22}{\pi } \\ = \frac{484}{\pi}$