Question

A wire can form a square of area 36 sq cm what is the area of rectangle when the same wire forms a rectangle in which one side is 2cm?

Answer 1

area of square = 36 cm²

side². =. 36

side = 6cm

now length of wire = perimeter of square

length of wire = 4 *6

length of wire = 24 cm

one side of rectangle = 2cm

so side opposite to it(length) = 2cm

other two sides(breadth) will be of 10 cm each

so area of rectangle = l*b

= 20 cm²

Answer 2

Answer:

$20cm^2$ is the required area of the rectangle.

Step-by-step explanation:

Explanation:

Given in the question that, area of a square is 36$cm^2$.

And also given that one side of a  rectangle  = 2cm.

Let breadth of the rectangle be 2cm.

Step 1:

From the question we have area of square = $36cm^2$.

And we know area of square = $side^2$ = $a^2$

⇒ 36 = $a^2$

⇒a = $\sqrt{36}$ = 6.

So, the side of square is 6cm.

Now according to the question, a wire can form a square and the same wire forms a rectangle.

So, the Perimeter of rectangle = Perimeter of square.

⇒2 (l + b) =   4a

⇒ 2 (l + 2) = 4 × 6      [side of square = a = 6cm and one side of rectangle = 2cm ]

⇒2l +  4 = 24

⇒l = $\frac{24 - 4 }{2}$  = 10cm

Step 2:

From step 1 we have length of rectangle = 10cm and breadth = 2cm.

So , the area of rectangle = l × b

⇒Area = 10 × 2 = 20$cm^2$.

Final answer:

Hence, the area of rectangle is $20cm^2$.

#SPJ3