Physics, asked by alan1757, 4 months ago

A wire carries 0.16 A steady current. Calculate the time required to pass 36 x 10 electrons in it is
a) 6 Min
b) 5 Min
5.5 Min
d) 7 Min

Answers

Answered by loyakushal04

0

I=q/t
0.16=36x10 x1.6x10^-19/t
t=36x10x1.6x10^-19/0.16

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