Question

a wire carries 0.16A steady current. claculate the time required to pass 36 * 10^19 electrons in it is

Answer 1

It has given that, a wire carries 0.16 Ampere steady current.

we have to calculate the time required to pass 36 × 10^19 electrons in it.

solution : we know, current is the rate of charge flowing through a wire in a specific time. in short, current is the ratio of charge and time.

I.e., i = Q/t

⇒Q = it

Here Q = charge passing through wire = 3.6 × 10^19 × charge on each electrons

= 3.6 × 10^19 × 1.6 × 10^-19 C = 3.6 × 1.6 C

i = current = 0.16A

Now, 3.6 × 1.6 = 0.16 × t

⇒t = 36 sec

therefore 36 seconds required to pass 3.6 × 10^19 electrons in the wire.

Answer 2

Answer:

we know, current is the rate of charge flowing through a wire in a specific time. in short, current is the ratio of charge and time.

I.e., i = Q/t

⇒Q = it

Here Q = charge passing through wire = 3.6 × 10^19 × charge on each electrons

= 3.6 × 10^19 × 1.6 × 10^-19 C = 3.6 × 1.6 C

i = current = 0.16A

Now, 3.6 × 1.6 = 0.16 × t

⇒t = 36 sec